思路：

ACcode:

#include<bits/stdc++.h>
using namespace std;
#define int long long
string s;
void solve() {cin>>s;s="00"+s;int len=s.size();for(int i=0; i<len; i++) {for(int j=i+1; j<len; j++) {for(int k=j+1; k<len; k++) {int x=s[i]*100+s[j]*10+s[k]-111*'0';if(x%8==0) {cout<<"YES\n"<<x<<"\n";return;}}}}cout<<"NO\n";
}
signed main() {ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);int t=1;//cin>>t;while(t--) {solve();}return 0;
}

over~