目录

• 1.isdisjoint的功能

• 2.isdisjoint的用法

• 3.代码

1.isdisjoint的功能

判断两个集合是否包含相同的元素。如果没有，返回True；如果有，返回False。

2.isdisjoint的用法

a_set = {'name','xiaomu','xiaoming'}
b_set = {'xiaoming','xiaogang','xiaohong'}
result = a_set.isdisjoint(b_set)
print(result)

运行结果：

False

3.代码

# coding:utf-8
company_not_allow ={'女','喝酒','抽烟','睡懒觉'}one_player = {'男','跑步','朝气','喝酒'}
two_player ={'女','生活规律','跆拳道'}
three_player ={'男','太极拳'}
four_player = {'男','空手道','年轻'}print(company_not_allow.isdisjoint(one_player))
print(company_not_allow.isdisjoint(two_player))
print(company_not_allow.isdisjoint(three_player))
print(company_not_allow.isdisjoint(four_player))

运行结果：

/Users/llq/PycharmProjects/pythonlearn/pythonlearn/python_set/bin/python /Users/llq/PycharmProjects/pythonlearn/python_set/set_isdis.py 
False
False
True
True进程已结束，退出代码为 0