OJ在线评测系统前端完善题目提交服务细讲异步前端请求与后端接口交互

题目提交服务完善

这则笔记是我们来梳理一下前后端逻辑

主要是我们的提交逻辑

先是看前端

按钮绑定的是这个异步请求

async 关键字表示这个函数内部会使用 await 来等待异步操作完成。

异步提交表单数据

const doSubmit = async () => {// message.error("刷题机架构尚未完成");console.log("尚未完善");if (!question.value?.id) {return;}const res = await QuestionControllerService.doQuestionSubmitUsingPost({...form.value,questionId: question.value.id,});// console.log(res.code);if (res.code === 0) {message.success("提交成功");} else {message.error("提交失败," + res.message);}
};

找一下请求

使用 await 关键字等待 QuestionControllerService.doQuestionSubmitUsingPost 异步请求的结果。这个请求将 form.value 对象的所有属性（使用了对象展开运算符 ...）以及 questionId 属性一起发送到服务器。questionId 从 question.value.id 中提取。

请求在这

  public static doQuestionSubmitUsingPost(questionSubmitAddRequest: QuestionSubmitAddRequest,): CancelablePromise<BaseResponse_long_ | any> {return __request(OpenAPI, {method: 'POST',url: '/question/question_submit/do',body: questionSubmitAddRequest,errors: {401: `Unauthorized`,403: `Forbidden`,404: `Not Found`,},});}

我们的请求找到了后端接口

首先我们看一下controller层表现层接口的的情况

@PostMapping("/question_submit/do")
public BaseResponse<Long> doQuestionSubmit(@RequestBody QuestionSubmitAddRequest questionSubmitAddRequest,HttpServletRequest request) {if (questionSubmitAddRequest == null || questionSubmitAddRequest.getQuestionId() <= 0) {throw new BusinessException(ErrorCode.PARAMS_ERROR);}final User loginUser = userService.getLoginUser(request);long questionSubmitId = questionSubmitService.doQuestionSubmit(questionSubmitAddRequest, loginUser);return ResultUtils.success(questionSubmitId);
}

在看我们的核心代码逻辑主要在service层里

在业务逻辑层我们看一下实现类里面是怎么书写具体逻辑的

@Override
public long doQuestionSubmit(QuestionSubmitAddRequest questionSubmitAddRequest, User loginUser) {// 校验编程语言是否合法String language = questionSubmitAddRequest.getLanguage();QuestionSubmitLanguageEnum languageEnum = QuestionSubmitLanguageEnum.getEnumByValue(language);if (languageEnum == null) {throw new BusinessException(ErrorCode.PARAMS_ERROR, "编程语言错误");}long questionId = questionSubmitAddRequest.getQuestionId();// 判断实体是否存在，根据类别获取实体Question question = questionService.getById(questionId);if (question == null) {throw new BusinessException(ErrorCode.NOT_FOUND_ERROR);}// 是否已提交题目long userId = loginUser.getId();// 每个用户串行提交题目QuestionSubmit questionSubmit = new QuestionSubmit();questionSubmit.setUserId(userId);questionSubmit.setQuestionId(questionId);questionSubmit.setCode(questionSubmitAddRequest.getCode());questionSubmit.setLanguage(language);// 设置初始状态questionSubmit.setStatus(QuestionSubmitStatusEnum.WAITING.getValue());questionSubmit.setJudgeInfo("{}");boolean save = this.save(questionSubmit);if (!save){throw new BusinessException(ErrorCode.SYSTEM_ERROR, "数据插入失败");}// todo 执行判题服务Long questionSubmitId = questionSubmit.getId();// 执行判题服务CompletableFuture.runAsync(() -> {judgeService.doJudge(questionSubmitId);});return questionSubmitId;
}