【python】python检测Harris角点 1.python提取Harris角点其实有在网上参考部分代码但是有些博客的博主可能连代码都没跑过直接网上找资源就粘贴在自己的博客下了然而有些代码是会报错的第一行就报错SyntaxError: invalid syntax应该是pre name code class python这一行代码出现的问题。但是我查阅了好多博客解释居然都一模一样直接这么复制黏贴真的好嘛我最后也没解决这个问题但是我发现这一行并不需要注释掉功能仍可以正常使用。如果有小伙伴能解释一下那我是完全欢迎的这里一共有两个.py文件第一个命名为harris.py相当于自己定义了一个module第二个看你喜好O(∩_∩)O# pre name code class python #coding:utf-8fromscipy.ndimageimportfiltersfromnumpyimport*frompylabimport*defcompute_harris_response(im,sigma3):imxzeros(im.shape)#计算导数filters.gaussian_filter(im,(sigma,sigma),(0,1),imx)imyzeros(im.shape)filters.gaussian_filter(im,(sigma,sigma),(1,0),imy)Wxxfilters.gaussian_filter(imx*imx,sigma)#计算harris矩阵分量Wxyfilters.gaussian_filter(imx*imy,sigma)Wyyfilters.gaussian_filter(imy*imy,sigma)#计算矩阵的特征值和迹WtrWxxWyyreturnWdet/Wtrdefget_harris_points(harrisim,min_dist10,threshold0.1):conner_thresholdharrisim.max()*threshold harrisim_t(harrisimconner_threshold)*1coordsarray(harrisim_t.nonzero()).T candidate_values[harrisim[c[0],c[1]]forcincoords]indexargsort(candidate_values)allowed_locationszeros(harrisim.shape)allowed_locations[min_dist:-min_dist,min_dist:-min_dist]1filtered_coords[]foriinindex:ifallowed_locations[coords[i,0],coords[i,1]]1:filtered_coords.append(coords[i])allowed_locations[(coords[i,0]-min_dist):(coords[i,0]min_dist),(coords[i,1]-min_dist):(coords[i,1]min_dist)]0#此处保证min_dist*min_dist只有一个harris特征点returnfiltered_coordsdefplot_harris_points(image,filtered_coords):figure()gray()imshow(image)plot([p[1]forpinfiltered_coords],[p[0]forpinfiltered_coords],)axis(off)show()#coding:utf-8fromscipy.ndimageimportfiltersfromnumpyimport*fromPILimportImageimportharrisfrompylabimport*forfilenameinos.listdir(r/path to your image):print(filename)imarray(Image.open(/path to your imagefilename).convert(L))harrisimharris.compute_harris_response(im)filtered_coordsharris.get_harris_points(harrisim,6)harris.plot_harris_points(im,filtered_coords)